Question

arcsiny／x的偏导数

Answer 1

• z=arcsiny/x

  ∂z/x=-arcsiny/x²

  ∂z/y=1/[x√(1-y²)]

• z=arcsin(y/x)

  ∂z/∂x=1/√[1-(y/x)²]·(-y/x²)=-y/[x√(x²-y²)]

  ∂z/∂y=1/√[1-(y/x)²]·(1/x)=1/√(x²-y²)