tana=√2-1 a是多少
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x = arctan (√2+1)tan2x = 2tanx/(1-tan^2x) = 2 (√2+1)/[1- (√2+1)^2] = -1Therefore, 2x = 3π/4x = 3π/8
咨询记录 · 回答于2023-01-03
tana=√2-1 a是多少
x = arctan (√2+1)tan2x = 2tanx/(1-tan^2x) = 2 (√2+1)/[1- (√2+1)^2] = -1Therefore, 2x = 3π/4x = 3π/8
等一下给你写√2-1的度数
x = arctan (√2-1)tan2x = 2tanx/(1+tan^2x) = 2 (√2-1)/[1+ (√2-1)^2]
等一下给你一个一个计算
x = arctan (√2-1)tan2x = 2tanx/(1-tan^2x) = 2 (√2-1)/[1+-(√2-1)^2]= 2 (√2-1)/[1-2+2√2-1]=√2-1/√2+1=2-2√2+1=3-2√2
斜率为√2-1，夹角为arctan(√2-1)。
√2-1=1.41-1=0.41
arctan0.41等于22度17分37.1秒
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