Question

帮忙解答，谢谢，需要过程

Answer 1

如图

Answer 2

(1)
f(x) = 1/√[(log<2>x)^2 -1]
x>0 (1) and
(log<2>x)^2 -1 ≥0
(log<2>x)^2 ≥1
log<2>x≥1 or log<2>x≤ -1
x≥2 or x≤1/2 (2)
f(x) = 1/√[(log<2>x)^2 -1] 定义域
(1) and (2)
x>0 and "x≥2 or x≤1/2"
=>x≥2 or 0<x≤1/2
(2)
f(x) = ln(x+1)/√(-x^2-3x+4)
x+1 >0
x> -1 (1)
-x^2-3x+4≥0
x^2+3x-4≤0
(x+4)(x-3)≤0
-4≤x≤3 (2)
f(x) = ln(x+1)/√(-x^2-3x+4) 定义域
(1) and (2)
x> -1 and -4≤x≤3
-1<x≤3

Answer 3

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