Question

因式分解

（x²-4x）（x²-4x-2）-15

（x+2）（x+4）（x+6）（x+8）+16

3a²-6ab+3b²-5a+5b

Answer 1

1.1.(x^2-4x)(x^2-4x-2)-15
=(x^2-4x)^2-2(x^2-4x)-15
=(x^2-4x-5)(x^2-4x+3)
=(x-5)(x+1)(x-3)(x-1)

2.(x+2)(x+4)(x+6)(x+8)+16
=[(x+2)(x+8)[[(x+4)(x+6)]+16
=(x^2+10x+16)(x^2+10x+24)+16
=(x^2+10x)^2+40(x^2+4x)+400
=(x^2+10x+20)^2

3.3a^2-6ab+3b^2-5a+5b
=(a-b)(3a-3b)-5(a-b)
=(a-b)(3a-3b-5)

Answer 2

头两道不知道你在写 什么 空格是什么意思

3a²-6ab+3b²-5a+5b
3(a-b)²-5(a-b)
(a-b)(3a-5-3b)

Answer 3

（x²-4x）（x²-4x-2）-15
=（x²-4x）^2-2（x²-4x）-15
=（x²-4x-5）（x²-4x+3）
=(x-5)(x+1)(x-1)(x-3)

（x+2）（x+4）（x+6）（x+8）+16
=(x+2)(x+8)(x+4)(x+6)+16
=(x²+10x+16)(x²+10x+24)+16
=(x²+10x+16)^2+8(x²+10x+16)+16
=[(x²+10x+16)+4]^2
=(x²+10x+20)^2
=(x+5+√5)^2*(x+5-√5)^2

3a²-6ab+3b²-5a+5b
=3(a-b)^2-5(a-b)
=(a-b)(3a-3b-5)