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√(3a²b)÷√(4ab²)
=(a√3b)/(2b√a)
=[(a√3b)·√a]/[(2b√a)·√a]
=(a√3ab)/(2ab)
=√(3ab)/(2b)
√[x(x+y)]÷√[xy²/(x+y)]
=√[x(x+y)]/{y√[x/(x+y)]}
={√[x(x+y)]√[x/(x+y)]}/{y√[x/(x+y)]²}
=x/[xy/(x+y)]
=(x+y)/y
=(a√3b)/(2b√a)
=[(a√3b)·√a]/[(2b√a)·√a]
=(a√3ab)/(2ab)
=√(3ab)/(2b)
√[x(x+y)]÷√[xy²/(x+y)]
=√[x(x+y)]/{y√[x/(x+y)]}
={√[x(x+y)]√[x/(x+y)]}/{y√[x/(x+y)]²}
=x/[xy/(x+y)]
=(x+y)/y
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