4个回答
展开全部
(5) f(x) = x(x-1)(x-2)(x-3),
f'(x) = (x-1)(x-2)(x-3) + x(x-2)(x-3) + x(x-1)(x-3) + x(x-1)(x-2)
f'(0) = (-1)(-2)(-3) = -6
f(0) = 0, f'(0) = 0
(4) f(x) = √(x+1) + (x^2-1)/[(x-1)(x+3)], 定义域 x ≥ -1, 即 x+3 > 0
间断点一个 x = 1, 选 A。
f'(x) = (x-1)(x-2)(x-3) + x(x-2)(x-3) + x(x-1)(x-3) + x(x-1)(x-2)
f'(0) = (-1)(-2)(-3) = -6
f(0) = 0, f'(0) = 0
(4) f(x) = √(x+1) + (x^2-1)/[(x-1)(x+3)], 定义域 x ≥ -1, 即 x+3 > 0
间断点一个 x = 1, 选 A。
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询