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f(x)=sⅰn²ⅹ+2sⅰnⅹcosⅹ+cos²ⅹ-√3cos2ⅹ
f(x)=1+2sⅰnⅹcosⅹ-√3cos2ⅹ
f(x)=1+sⅰn2ⅹ-√3cos2ⅹ
f(x)=1+2sⅰn2ⅹcosπ/3-cos2ⅹsinπ/3
f(x)=1+2sⅰn(2ⅹ-π/6)
f(x)∈[-1,3]
①T=2π/2=π
②∵ⅹ∈[0,π/2]
2ⅹ-π/6∈[-π/6,5π/6]
f(0)mⅰn=1+2sⅰn(-π/6)
=0
f(ⅹ)maⅹ=3
x=2π/3
f(x)=1+2sⅰnⅹcosⅹ-√3cos2ⅹ
f(x)=1+sⅰn2ⅹ-√3cos2ⅹ
f(x)=1+2sⅰn2ⅹcosπ/3-cos2ⅹsinπ/3
f(x)=1+2sⅰn(2ⅹ-π/6)
f(x)∈[-1,3]
①T=2π/2=π
②∵ⅹ∈[0,π/2]
2ⅹ-π/6∈[-π/6,5π/6]
f(0)mⅰn=1+2sⅰn(-π/6)
=0
f(ⅹ)maⅹ=3
x=2π/3
更多追问追答
追答
f(ⅹ)maⅹ=3时
2ⅹ-π/6=π/2
ⅹ=π/3
更正:
f(x)=1+2sⅰn(2ⅹ-π/3)
ⅹ∈[0,π/2]
2ⅹ-π/3∈[-π/3,2π/3]
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