问下这道高等数学求积分怎么写？
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记唯判御 r^2 = u, k = sinθcosθ
I = (1/2) ∫(1+ku)du/(1+u)
= (1/2) ∫(k+ku+1-k)du/冲蚂(1+u)
= (1/2) ∫[k+(1-k)/(1+u)]du
= (1/2)[ku + (1-k)ln(1+u) + C
= (1/指岩2)[r^2*sinθcosθ + (1-sinθcosθ)ln(1+r^2) + C
I = (1/2) ∫(1+ku)du/(1+u)
= (1/2) ∫(k+ku+1-k)du/冲蚂(1+u)
= (1/2) ∫[k+(1-k)/(1+u)]du
= (1/2)[ku + (1-k)ln(1+u) + C
= (1/指岩2)[r^2*sinθcosθ + (1-sinθcosθ)ln(1+r^2) + C
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