Question

要得到函数y=2cos(2x+π/3)的图像,只需将函数y=sin2x+根号3cos2x的图象?

Answer 1

y=sin2x+√3cos2x
=2*[sin2x*(1/2)+cos2x*(√3/2)]
=2*[sin2x*cos(π/3)+cos2x*sin(π/3)]
=2*sin[2x+(π/3)]
=2cos（2x+π/3-π/2）
=2cos[2(x-π/4)+π/3]
所以向右平移π/4个单位