Question

用C# vs 编写一个简易的计算器

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Answer 1

Console.Write("请输入第一个数字：");
double num1 = Convert.toDouble(Console.ReadLine());
Console.Write("请输入运算符(+、-、*、/)：");
string p = Console.ReadLine();
Console.Write("请输入第二个数字：");
double num2 = Convert.toDouble(Console.ReadLine());
double result;
switch(p){
case "+":
result = num1 + num2;
break;
case "-":
result = num1 - num2;
break;
case "*":
result = num1 * num2;
break;
case "/":
result = num1 / num2;
break;
}

Console.WriteLine(num1 + p + num2 + "的结果为：" + result);
Console.ReadKey();