Question

输入10个整数到数组a，将数组a中的数倒序放入数组b，输出a和b中所有对应元素的和

Answer 1

#include <iostream.h>

void sort(int a[], int num)
{
for (int i = 0; i < num-1; i++)
{
for (int j = num-1; j > i; j--)
{
if (a[j] > a[j-1])
{
int tmp = a[j-1];
a[j-1] = a[j];
a[j] = tmp;
}
}
}
}

void disply(int y[], int num)
{
for (int x = 0; x < num; x++)
{
cout << y[x] << " ";
}
cout << '\n';
}

void yourway(int s[], int d[], int num)
{
cout << "plesea input: " << endl;
for (int x = 0; x < 10; x++)
{
cin >> s[x];
}
cout <<"finished: "<<endl;
for (int x = 0; x < num; x++)
{
d[x] = s[x];
}
sort(d,10);
cout <<"source: ";
disply(s,10);
cout <<"destination: ";
disply(d,10);
}

int main()
{
int a[10], b[10];
yourway(b,a,10);

return 0;
}

Answer 2

#include <stdio.h>
void main()
{
int a[10],b[10],i;
for(i=0;i<10;i++)
scanf("%d",&a[i]);
for(i=9;i>=0;i--)
b[9-i]=a[i];
for(i=0;i<10;i++)
printf("a%d+b%d=%d\n",i,i,a[i]+b[i]);
}