Question

关于概率论与数理统计题。

第五题，帮忙详细解答谢谢~

Answer 1

P(A∩(~B)) =P((~A)∩B) = 1/4
P(A)-P(A∩B) = P(B) -P(A∩B) = 1/4
=>P(A)=P(B)
P(A∩B) =P(A)P(B) =[P(A)]^2
P(A)-P(A∩B) = 1/4
P(A) -[P(A)]^2 = 1/4
4[P(A)]^2 - 4P(A) +1=0
(2P(A)-1)^2=0
P(A) =1/2
=>P(A)=P(B)=1/2