Question

5、7、8、13这组数字如何得出24?

Answer 1

加减乘除无法得到.
如果允许开立方可以
8的立方根是2
5 7 2 13
5-(7-(2*13))
(5-7)+(2*13)
((5*7)+2)-13
(5*7)+(2-13)
5-(7-(13*2))
(5-7)+(13*2)
(5*7)-(13-2)
((5*7)-13)+2
((5*7)+13)/2
5+((2*13)-7)
(5+(2*13))-7
5+((13*2)-7)
(5+(13*2))-7
((7*5)+2)-13
(7*5)+(2-13)
((7-5)*13)-2
(7*5)-(13-2)
((7*5)-13)+2
((7*5)+13)/2
2+((5*7)-13)
(2+(5*7))-13
2+((7*5)-13)
(2+(7*5))-13
2-(13-(5*7))
(2-13)+(5*7)
((2*13)+5)-7
(2*13)+(5-7)
2-(13-(7*5))
(2-13)+(7*5)
(2*13)-(7-5)
((2*13)-7)+5
(13+(5*7))/2
(13+(7*5))/2
(13*(7-5))-2
((13*2)+5)-7
(13*2)+(5-7)
(13*2)-(7-5)
((13*2)-7)+5
----END----