Question

数学知识交流---整数部份(2)

Answer 1

1)12/34 + 56/78 + 90/12 + 34/56 + 78/90= (12/34 + 34/56) + (56/78 + 78/90) + 90/12利用 A.M. > G.M. :> 2√[(12/34)(34/56)] + 2√[(56/78)(78/90)] + 90/12= 2√(12/56) + 2√(56/90) + 90/12= 2√[(3/7)(4/8)] + 2√[(7/9)(8/10)] + 90/12> 2(3/7) + 2(7/9) + 90/12 = 6/7 + (1+5/9) + 7.5= 9.9....推测整数部份极可能是 10 。而 12/34 + 56/78 + 90/12 + 34/56 + 78/90 - 10= (12/34 - 1) + (56/78 - 1) + (90/12 - 6) + (34/56 - 1) + (78/90 - 1)= - 22/34 - 22/78 + 3/2 - 22/56 - 12/90≈ - 22/33 - 22/77 + 3/2 - 22/55 - 2/15≈ 3/2 - (2/3 + 2/7 + 2/5 + 2/15)≈ 3/2 - 2(1/3 + 1/7 + 1/5 + 1/15)≈ 3/2 - 2(26/35)≈ 1/70> 0故 12/34 + 56/78 + 90/12 + 34/56 + 78/90 的整数部份的确为10。 2)1/2 + 1/3 + 1/4 + 1/5 + 1/6 + 1/7 + 1/8 + 1/9 + 1/10= (1/2 + 1/3 + 1/6) + (1/4 + 1/5) + (1/7 + 1/8 + 1/9 + 1/10)< 1 + (1/4 + 1/4) + (1/7 + 1/7 + 1/7 + 1/7)= 1 + 1/2 + 3/7 < 2故其整数部份是 1。 2011-06-02 23:40:46 补充： 修正 2) 1/2 + 1/3 + 1/4 + 1/5 + 1/6 + 1/7 + 1/8 + 1/9 + 1/10 = (1/2 + 1/3 + 1/6) + (1/4 + 1/5 + 1/10) + (1/7 + 1/8 + 1/9) = (1) + (0.55) + (1/7 + 1/8 + 1/9) < 1.55 + (1/7 + 1/7 + 1/7) = 1.55 + 3/7 = 1.55 + 0.42857... < 2 故其整数部份是 1。 2011-06-03 13:23:52 补充： 1)'s solution proves the integral part of (12/34 + 56/78 + 90/12 + 34/56 + 78/90) ≈ 10 + 1/70 < 11 2011-06-03 13:40:45 补充： 这样会清楚些 : (12/34 + 56/78 + 90/12 + 34/56 + 78/90) = (1 - 22/34) + (1 - 22/78) + 7.5 + (1 - 22/56) + (1 - 12/90) = 11.5 - (22/34 + 22/78 + 22/56 + 2/15) >≈ 11.5 - (22/33 + 22/77 + 22/55 + 2/15) = 11.5 - 2(1/3 + 1/7 + 1/5 + 1/15) = 11.5 - 2(26/35) = 10 + 1/70
(1)'s solution only proves the integral part of (12/34+56/78+90/12+34/56+78/90) ≧10
but why is it 10 instead of 11
12
13
14
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(1) the result is: 310783 / 30940 = 10 + 1383 / 30940 so the 整数部分 is 10. 2011-06-02 20:38:48 补充： (2) the result is: 4861 / 2520 = 1 + 2341 / 2520 so the 整数部分 is 1.