Question

请各位高手看看我的LINGO程序错误在哪？错我提示为12。但我找不到错误

sets:
document/a1..a8/:size;
datatraveler/b1..b5/:capacity;
links(document,datatraveler):c
endsets
!目标函数；
max=@sum@sum(size(I)*c(I,J)/capacity(J));
!约束条件；
@for(document(I):
@sum(datatraveler(J):c(I,J)=1);
@for(datatraveler(J):
@sum(document(I):c(I,J)*size(I)<=capacity(J));
size(I)>0
capacity(J)>0;

data:
size=0.08 0.3 0.6 1.4 2.8 3.2 4.5 5.6;
capacity=2 4 8 12 16;
@for(links:@bin(c));
enddata
end
还有，到底怎么编写双求和符号的程序？也就是两个求和符号连乘

Answer 1

错误比较多，恕不一一指出，修改后的代码：
model:
sets:
document/a1..a8/:size;
datatraveler/b1..b5/:capacity;
links(document,datatraveler):c;
endsets
!目标函数;
max=@sum(datatraveler(J):@sum(document(I):size(I)*c(I,J))/capacity(J));
!约束条件;
@for(document(I):
@sum(datatraveler(J):c(I,J))=1);
@for(datatraveler(J):
@sum(document(I):c(I,J)*size(I))<=capacity(J));
data:
size=0.08 0.3 0.6 1.4 2.8 3.2 4.5 5.6;
capacity=2 4 8 12 16;
enddata
@for(links:@bin(c));
end
运行结果：
Global optimal solution found at iteration: 0
Objective value: 3.274167

Variable Value Reduced Cost
SIZE( A1) 0.8000000E-01 0.000000
SIZE( A2) 0.3000000 0.000000
SIZE( A3) 0.6000000 0.000000
SIZE( A4) 1.400000 0.000000
SIZE( A5) 2.800000 0.000000
SIZE( A6) 3.200000 0.000000
SIZE( A7) 4.500000 0.000000
SIZE( A8) 5.600000 0.000000
CAPACITY( B1) 2.000000 0.000000
CAPACITY( B2) 4.000000 0.000000
CAPACITY( B3) 8.000000 0.000000
CAPACITY( B4) 12.00000 0.000000
CAPACITY( B5) 16.00000 0.000000
C( A1, B1) 0.000000 -0.4000000E-01
C( A1, B2) 1.000000 -0.2000000E-01
C( A1, B3) 0.000000 -0.1000000E-01
C( A1, B4) 0.000000 -0.6666667E-02
C( A1, B5) 0.000000 -0.5000000E-02
C( A2, B1) 0.000000 -0.1500000
C( A2, B2) 1.000000 -0.7500000E-01
C( A2, B3) 0.000000 -0.3750000E-01
C( A2, B4) 0.000000 -0.2500000E-01
C( A2, B5) 0.000000 -0.1875000E-01
C( A3, B1) 1.000000 -0.3000000
C( A3, B2) 0.000000 -0.1500000
C( A3, B3) 0.000000 -0.7500000E-01
C( A3, B4) 0.000000 -0.5000000E-01
C( A3, B5) 0.000000 -0.3750000E-01
C( A4, B1) 1.000000 -0.7000000
C( A4, B2) 0.000000 -0.3500000
C( A4, B3) 0.000000 -0.1750000
C( A4, B4) 0.000000 -0.1166667
C( A4, B5) 0.000000 -0.8750000E-01
C( A5, B1) 0.000000 -1.400000
C( A5, B2) 0.000000 -0.7000000
C( A5, B3) 1.000000 -0.3500000
C( A5, B4) 0.000000 -0.2333333
C( A5, B5) 0.000000 -0.1750000
C( A6, B1) 0.000000 -1.600000
C( A6, B2) 1.000000 -0.8000000
C( A6, B3) 0.000000 -0.4000000
C( A6, B4) 0.000000 -0.2666667
C( A6, B5) 0.000000 -0.2000000
C( A7, B1) 0.000000 -2.250000
C( A7, B2) 0.000000 -1.125000
C( A7, B3) 1.000000 -0.5625000
C( A7, B4) 0.000000 -0.3750000
C( A7, B5) 0.000000 -0.2812500
C( A8, B1) 0.000000 -2.800000
C( A8, B2) 0.000000 -1.400000
C( A8, B3) 0.000000 -0.7000000
C( A8, B4) 1.000000 -0.4666667
C( A8, B5) 0.000000 -0.3500000

Row Slack or Surplus Dual Price
1 3.274167 1.000000
2 0.000000 0.000000
3 0.000000 0.000000
4 0.000000 0.000000
5 0.000000 0.000000
6 0.000000 0.000000
7 0.000000 0.000000
8 0.000000 0.000000
9 0.000000 0.000000
10 0.000000 0.000000
11 0.4200000 0.000000
12 0.7000000 0.000000
13 6.400000 0.000000
14 16.00000 0.000000

如有疑问，请留言。

Answer 2

上面的好强啊，能帮我看看吗？

http://zhidao.baidu.com/question/148176335.html