Question

x(a-x)(a-y)-y(x-a)(y-a)怎么因式分解

我要过程

Answer 1

x(a-x)(a-y)-y(x-a)(y-a)
=(x-y)(a-x)(a-y)
因为同时改变式子中的两个数的符号结果还相等，所以（x-a)(y-a)=(a-x)(a-y)

Answer 2

x(a-x)(a-y)-y(x-a)(y-a)为原式
原式=x(a-x)(a-y)-y[-1(a-x)][-1(a-y)]
（两个-1相乘得正数）
得到：x(a-x)(a-y)-y(a-x)(a-y)
提取同项式得到答案：(a-x)(a-y)(x-y)

Answer 3

x(a-x)(a-y)-y(x-a)(y-a)
=x(a-x)(a-y)-y[-(a-x)][-(a-y)]
=x(a-x)(a-y)-y(a-x)(a-y)
=(a-x)(a-y)(x-y)

Answer 4

x(a-x)(a-y)-y(x-a)(y-a)
=x(a-x)(a-y)-y(a-x)(a-y)
=(a-x)(a-y)（x-y）