Question

怎样计算2＋2²+2³.....2^10过程

Answer 1

{2-【-2的平方+10-（-2）的平方】*1/2的立方}*（-10）的立方的过程啊 ={2-[-22+10-(-2)2]*(1/2)3}*(-10)3 ={2-[-4+10-4]*(1/8)}*(-103) ={2-[2]*(1/8)}*(-103) ={2-1/4}*(-103) =(7/4)(-103) =-7*250 =-1750

Answer 2

2＋2²+2³.....2^10
=2*（1-2^10）÷（1-2）
=2^11-2

Answer 3

22+42+62+82+……+(2n)2 =4×(12+22+32+42+……+n2) =4×[(1/6)n(n+1)(2n+1)] =(2/3)n(n+1)(2n+1)