请求高人帮我解一道英文数学题
Asidewalkistobeconstructedaroundaswimmingpoolthatmeasures(10.0±0.1)mby(17.0±0.1)m.Ift...
A sidewalk is to be constructed around a swimming pool that measures (10.0 ± 0.1) m by (17.0 ± 0.1) m. If the sidewalk is to measure (1.00 ± 0.01) m wide by (9.0 ± 0.1) cm thick, what volume of concrete is needed, and what is the approximate uncertainty of this volume?
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【翻译】
一个游泳池周围要建人行道,游泳池的长宽是10.0(±0.1)米×17.0±(0.1
),米如果人行道是1.00
(±
0.01)米宽,9.0±(0.1)厘米厚。那么需要多少体积混凝土,有多少不确定度?
先来计算总体积:
V=[10.0×1.00×2+(17.0-2.0)×1.00×2]×0.090=4.5立方米
V(Max)=[10.1×1.01×2+(17.1-2.02)×1.01×2]×0.091=4.629立方米
V(Min)=[9.99×0.99×2+(16.9-1.98)×0.99×2]×0.089=4.374立方米
所以不确定度为+0.129和-0.126
用英文解答如下:
Sol:Volume
of
concrete=[10.0×1.00×2+(17.0-2.0)×1.00×2]×0.090=4.5m^3
V(Max)=[10.1×1.01×2+(17.1-2.02)×1.01×2]×0.091=4.629
m^3
V(Min)=[9.99×0.99×2+(16.9-1.98)×0.99×2]×0.089=4.374
m^3
Approximate
uncertainty=
±0.13
一个游泳池周围要建人行道,游泳池的长宽是10.0(±0.1)米×17.0±(0.1
),米如果人行道是1.00
(±
0.01)米宽,9.0±(0.1)厘米厚。那么需要多少体积混凝土,有多少不确定度?
先来计算总体积:
V=[10.0×1.00×2+(17.0-2.0)×1.00×2]×0.090=4.5立方米
V(Max)=[10.1×1.01×2+(17.1-2.02)×1.01×2]×0.091=4.629立方米
V(Min)=[9.99×0.99×2+(16.9-1.98)×0.99×2]×0.089=4.374立方米
所以不确定度为+0.129和-0.126
用英文解答如下:
Sol:Volume
of
concrete=[10.0×1.00×2+(17.0-2.0)×1.00×2]×0.090=4.5m^3
V(Max)=[10.1×1.01×2+(17.1-2.02)×1.01×2]×0.091=4.629
m^3
V(Min)=[9.99×0.99×2+(16.9-1.98)×0.99×2]×0.089=4.374
m^3
Approximate
uncertainty=
±0.13
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