Question

解:(x-2)(x-3)<0的求解方式

Answer 1

解：（1）(x-2)/(x+3)≥0 (x-2)(x+3)≥0且x+3≠0 解得x≥2或x＜-3（2）x^2+x-20<0, x-1>2①(x-4)(x+5)＜0 解得-5＜x＜4②x-1＞2 x-1＞2或x-1＜-2解得x＞3或x＜-1由①、②取交集得：{x-5＜x＜-1或3＜x＜4}