
已知等差数列{an}的前n项和为Sn,且a4-a2=4,S5=30等比数列{bn}中,bn+1=3bn,n∈N+,b1=3.(1)求an,b
已知等差数列{an}的前n项和为Sn,且a4-a2=4,S5=30等比数列{bn}中,bn+1=3bn,n∈N+,b1=3.(1)求an,bn;(2)求数列{an?bn}...
已知等差数列{an}的前n项和为Sn,且a4-a2=4,S5=30等比数列{bn}中,bn+1=3bn,n∈N+,b1=3.(1)求an,bn;(2)求数列{an?bn}的前n项和Tn.
展开
1个回答
展开全部
(1)等差数列{an}中,∵a4-a2=4,∴2a=4,∴d=2
∵S5=30,∴5a1+10d=30,∴a1=2
∴an=2n;
等比数列{bn}中,bn+1=3bn,b1=3,∴bn=3?3n?1=3n;
(2)Tn=2?31+4?32+…+2n?3n
∴3Tn=2?32+4?33+…+(2n?2)?3n+2n?3n+1
两式相减可得?2Tn=2?31+2?32+4?32+…+2?3n?2n?3n+1=-3-(2n-1)?3n+1
∴Tn=
?3n+1+
.
∵S5=30,∴5a1+10d=30,∴a1=2
∴an=2n;
等比数列{bn}中,bn+1=3bn,b1=3,∴bn=3?3n?1=3n;
(2)Tn=2?31+4?32+…+2n?3n
∴3Tn=2?32+4?33+…+(2n?2)?3n+2n?3n+1
两式相减可得?2Tn=2?31+2?32+4?32+…+2?3n?2n?3n+1=-3-(2n-1)?3n+1
∴Tn=
2n?1 |
2 |
3 |
2 |
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询