Question

springmvc配置的返回json java端怎么写

Answer 1

package xxx;
import java.io.PrintWriter;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import net.sf.json.JSONArray;
import net.sf.json.JSONObject;

public class ProtocolHelper {

	public static void writeJSON2Response(JSONObject json,
			HttpServletResponse response) throws Exception {
		response.setContentType("text/json;charset=UTF-8");
		PrintWriter out = response.getWriter();
		out.print(json);
		out.flush();
		out.close();
	}
	
	public static void writeJSON2AJAXResponse(HttpServletRequest request, 
			JSONObject json,
			HttpServletResponse response) throws Exception {
		response.setContentType("text/json;charset=UTF-8");
		String callback = request.getParameter("callback"); 
        PrintWriter out = response.getWriter(); 
        out.print(callback+"("+json+")"); 
        out.flush();
        out.close();
	}
	

	public static void writeJSON2Response(JSONArray json,
			HttpServletResponse response) throws Exception {
		response.setContentType("text/json;charset=UTF-8");
		PrintWriter out = response.getWriter();
		out.print(json);
		out.flush();
		out.close();
	}
}

上面是返回json数据的工具类
在action中你可以使用
JSONObject json = new JSONObject();
json.put("status", "success");
ProtocolHelper.writeJSON2Response(json, response);
来向前端返回你想要传输的json数据