Question

高一数学题求解答

Answer 1

请

Answer 2

M={x|x^2+6-6=0} ={x|(x+3)(x-2)=0} ={ -3,2}

N={x|ax-1=0}

N⊆M 

case 1: N=Φ

a=0

N⊆M 

case 2: N≠Φ

a≠0

N={x|ax-1=0} = { 1/a}

N⊆M 

1/a =-3 or 2

a= -1/3 or 1/2

/

N⊆M 

case 1 or case 2

a=0 or -1/3 or 1/2