Question

求极限，要详解过程

Answer 1

给你最详细解答。

追答

等价无穷小替换。

追问

懂了，谢谢

Answer 2

x->0
sinx = x-(1/6)x^3 +o(x^3)
sinx/x =1-(1/6)x^2 +o(x^2)
ln(sinx/x)
=ln[1-(1/6)x^2 +o(x^2)]
=-(1/6)x^2 +o(x^2)
lim(x->0) ln(sinx/x) /x^2
=lim(x->0) -(1/6)x^2 /x^2
=-1/6