Question

方程xy-sin(派y^2)=0确定y是x的函数,求Y'(X=0,Y=-1)一阶导数,Y''(X=0,Y=-1)二阶导数,

Answer 1

两边对x求导：
y+xy'-cos(πy^2)*(2πyy')=0
得：y'=y/[2πycos(πy^2)-x]