Question

springmvc controller怎么获取一个输入流

Answer 1

springmvc 中controller获取ajax数据的方法：
1、页面jsp代码：
<table style="width: 100%" class="table" cellspacing="1" cellpadding="1" border="0">
<tr><td class="ti1" colSpan="2">请选择审讯室</td></tr>
<tr><td class="ti2hui">审讯室名称</td><td class="ti1cu">
<select id="roomid" name="roomid" >
<c:forEach items="${roomlist}" var="room">
<option value ="${room.id}">${room.name}</option>
</c:forEach>
</select>
</td></tr>
<tr><td class="ti2hui" colSpan="2" align="center"><input type="button" onclick="setshow()" value="确定"/> </td></tr>
</table>
点击确定后触发ajax接口：
function setshow(){
$.ajax( {
type : "POST",
url : "<%=request.getContextPath()%>/initroom.do?method=set",
data : {
'room' : $("#roomid").find('option:selected').text(),
'roomid' :$("#roomid").val()
},
dataType: "json",
success : function(data) {
if(data.success){
alert("设置成功！");

}
else{
alert("设置失败！");
}
},
error :function(){
alert("网络连接出错！");
}
});
}
2、后台controller写法：
@RequestMapping(params = "method=set")
public void jump(HttpSession session,HttpServletRequest request, HttpServletResponse response) throws Exception{
String roomid= request.getParameter("roomid");
String room= request.getParameter("room");
session.setAttribute("ROOMID", roomid);
session.setAttribute("ROOMNAME", room);
System.out.println("session set:"+room+"=="+roomid);
response.setCharacterEncoding("utf-8");
response.getWriter().write("{\"success\":true }");
response.getWriter().flush();
}
3、springmvc 返回信息到ajax:
import com.googlecode.jsonplugin.JSONUtil;
List<Records> recordList = new ArrayList<Records>();
//获取recordlist操作省略
response.setCharacterEncoding("utf-8");
response.getWriter().write("{\"success\":true, \"data\":" + JSONUtil.serialize(recordList) + "}");
response.getWriter().flush();