Question

分解因式 数学题（初三）

用分解因式法解下列方法。
要有步骤

（最好上图，要不有的看不懂）

Answer 1

2(x-3)²=x²-9
2(x-3)²-(x²-9)=0
2(x-3)²-(x-3)(x+3)=0
(x-3)(2x-6-x-3)=0
(x-3)(x-9)=0
x-3=0 或 x-9=0
x=3 或 x=9

Answer 2

2(x-3)²=x²-9
2(x²-6x+9)=x²-9
2x²-12x+18=x²-9
2x²-x²-12x+18+9=0
x²-12x+27=0
x²-12x+36=9
(x-6)²=9
x-6=±3
x=3 或x=9

Answer 3

2(x-3)^2=x^2-9
2(x-3)^2-(x^2-9) =0
2(x-3)^2-(x-3)(x+3) =0
(x-3)[2(x-3)-(x+3)] =0
(x-3)(2x-6-x-3) =0
(x-3)(x-9) =0
x=3或x=9

Answer 4

3或9

Answer 5

X=3或X=9

Answer 6

2(x-3)²=x²-9
2(x-3)²-(x-3)(x+3)=0
(x-3)(2x-6-x-3)=0
(x-3)(x-9)=0
x-3=0 或 x-9=0
x=3 或 x=9