一道数学题,在线等,急!
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D(xy)=E(x²y²)-E²(xy)=E(x²)E(y²)-E²(x)E²(y)
D(x)=E(x²)-E²(x)
D(y)=E(y²)-E²(y)
E²(x)>=0
E(x²)>=0
所以
D(x)D(y)=E(x²)E(y²)-E²(x)E²(y)-E²(x)E(y²)-E(x²)E²(y)
=D(xy)-E²(x)E(y²)-E(x²)E²(y)<=D(xy)
如有意见,欢迎讨论,共同学习;如有帮助,请选为满意回答!
D(x)=E(x²)-E²(x)
D(y)=E(y²)-E²(y)
E²(x)>=0
E(x²)>=0
所以
D(x)D(y)=E(x²)E(y²)-E²(x)E²(y)-E²(x)E(y²)-E(x²)E²(y)
=D(xy)-E²(x)E(y²)-E(x²)E²(y)<=D(xy)
如有意见,欢迎讨论,共同学习;如有帮助,请选为满意回答!
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