数电== 将逻辑函数化为或非-或非形式Y=(ABC'+B'C)'D+A'B'D 求大神教教怎么做
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Y = (ABC' + B'C)'D + A'B'D
= (ABC')' ( B'C)' D + A'B'D
= (A' + B' + C) (BD + C'D) + A'B'D
= A'BD + A'C'D + 0 + B'C'D + BCD + 0 + A'B'D
= A'D (B + B') + A'C'D + B'C'D + BCD
= A'D + A'C'D + B'C'D + BCD
= A'D (1 + C') + B'C'D + BCD
= A'D + B'C'D + BCD
= (A' + B'C' + BC) D
= ( (A' + B'C' + BC) )' + D’ )'
= ( (A' + B⊙C )' + D' )'
= (ABC')' ( B'C)' D + A'B'D
= (A' + B' + C) (BD + C'D) + A'B'D
= A'BD + A'C'D + 0 + B'C'D + BCD + 0 + A'B'D
= A'D (B + B') + A'C'D + B'C'D + BCD
= A'D + A'C'D + B'C'D + BCD
= A'D (1 + C') + B'C'D + BCD
= A'D + B'C'D + BCD
= (A' + B'C' + BC) D
= ( (A' + B'C' + BC) )' + D’ )'
= ( (A' + B⊙C )' + D' )'
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