Question

(x-4)(x-4)-(5-2x)(5-2x)=0用因式分解法解方程

Answer 1

(x-4)(x-4)-(5-2x)(5-2x)=0
(x-4)^2-(5-2x)^2=0
(x-4+5-2x)(x-4-5+2x)=0
(-x+1)(3x-9)=0
3(-x+1)(x-3)=0
所以-x+1=0或x-3=0或碧陪乱-x+1=0,x-3=0
解乱搭得分别悔档为x=1,x=3,(x=1,x=3)
所以x1=1,x2=3

Answer 2

平方禅仿纤贺仿差大厅
[(x-4)+(5-2x)][(x-4)-(5-2x)]=0
(-x+1)(3x-9)=0
3(x-1)(x-3)=0
x=1,x=3

Answer 3

(x-4)(x-4)-(5-2x)(5-2x)=0
x²差散镇-8x+16-（4x²-20x+25）=0
x²虚粗-8x+16-4x²+20x-25=0
3x²掘大-12x+8=0
（3x-8）（x-1）=0
x=3/8或x=1

Answer 4

（纳握x-4)(x-4)-(5-2x)(5-2x)=0
x²庆数-8x+16-25+20x-4x²=0
-3x²誉茄首+12x-9=0
-3(x²-4x+3)=0
-3(x-1)(x-3)=0
x=1 x=3