Question

利用克拉默法则，求解下列线性方！！求详细解答过程，谢谢方程组如下X1+2X2+3X3=22X1+2X2+5X3=13X1+5X2+X3=-1

Answer 1

问：利用克拉默法则，求解下列线性方！！求详细解答过程，谢谢方程组如下X1+2X2+3X3=22X1+2X2+5X3=13X1+5X2+X3=-1

答：根据克拉默法则，该线性方程组的系数行列式为| 1 0 1 |D = | 2 2 3 | = 1 x (2 - 3) + 1 x (2 - 0) = 1| 0 1 1 |而各个未知数对应的行列式分别为| 1 0 1 |D1 = | 3 2 3 | = 1 x (2 - 3) + 1 x (3 + 2) = 4| -1 1 1 || 1 1 1 |D2 = | 2 3 3 | = 1 x (3 + 3) - 1 x (2 - 0) + 1 x (-2 - 0) = 2| 0 -1 1 || 1 0 1 |D3 = | 2 2 3 | = 1 x (-2 - 3) + 1 x (2 - 0) = -3| 0 1 -1 |根据克拉默法则x1 = D1/D = 4，x2 = D2/D = 2，x3 = D3/D = -3。