1个回答
展开全部
2x(x-y)^4 - x²(x-y)² + xy(y-x)²
=2x(x-y)^4 - x²(x-y)² + xy(x-y)²
=x(x-y)^2[2(x-y)² - x + y]
=x(x-y)^2[2(x-y)² - (x-y)]
=x(x-y)^2*(x-y)[2(x-y)-1]
=x(x-y)^3[2(x-y)-1]
=x(x-y)^3(2x-2y-1)
=2x(x-y)^4 - x²(x-y)² + xy(x-y)²
=x(x-y)^2[2(x-y)² - x + y]
=x(x-y)^2[2(x-y)² - (x-y)]
=x(x-y)^2*(x-y)[2(x-y)-1]
=x(x-y)^3[2(x-y)-1]
=x(x-y)^3(2x-2y-1)
本回答由提问者推荐
已赞过
已踩过<
评论
收起
你对这个回答的评价是？
推荐律师服务：
若未解决您的问题，请您详细描述您的问题，通过百度律临进行免费专业咨询
