Question

c#随机数方法产生5个1~10（包括1和10）之间的整数。

Answer 1

int[] s = new int[5];//s数组中存放着需要的数字
Random ra = new Random();
for (int i = 0; i < 5; i++)//遍历数组显示结果
{
s[i] = ra.Next(1, 10);
Console.WriteLine(s[i]);
}
Console.ReadKey();

Answer 2

/// <summary>
/// 生成随机数字
/// </summary>
/// <param name="Length">生成长度</param>
/// <returns></returns>
public static string Number(int Length)
{
string result = "";
System.Random random = new Random();
for (int i = 0; i < Length; i++)
{
result += random.Next(10).ToString();
}
return result;
}
调用
string aa = Number(5);
aa就是 5个 随机数

Answer 3

Random rand = new Random(DateTime.Millisecond);
for(int i = 0;i<5;i++)
{
int x = rand.Next(1,10);
Console.WriteLine(x.ToString());

}

Answer 4

public string GetNum(){
string num = "";
Random random = new Random();
for(int i = 0;i<5;i++){
num = num+random.Next(1,10);
}
return num;
}