怎么用java编程,实现分数的加减乘除运算?

 我来答
育知同创教育
2016-03-10 · 百度知道合伙人官方认证企业
育知同创教育
1【专注:Python+人工智能|Java大数据|HTML5培训】 2【免费提供名师直播课堂、公开课及视频教程】 3【地址:北京市昌平区三旗百汇物美大卖场2层,微信公众号:yuzhitc】
向TA提问
展开全部

    java编程实现分数的加减乘除运算的步骤如下:

    1、打开eclipse,创建一个Java工程,在此工程里新建一个类;

    2、在新建的类中,添加4个运算类;

    3、在主方法中调用对应的方法即可完成分数的加减乘除运算了。

    具体实现代码如下:

     public class Demo {
    public static void main(String[] args) {
        System.out.println(jia(1, 2));
        System.out.println(jian(1, 2));
        System.out.println(cheng(1, 2));
        System.out.println(chu(1, 2));
    }
    //加法运算
    private static float jia(float x,float y) {
        return x + y;
    }
    //减法运算
    private static float jian(float x,float y) {
        return x - y;
    }
    //乘法运算
    private static float cheng(float x,float y) {
        return x * y;
    }
    //除法运算
    private static float chu(float x,float y) {
        return x / y;
    }
}
西窗夜雨潇湘
2018-04-11 · TA获得超过8002个赞
知道小有建树答主
回答量:27
采纳率:0%
帮助的人:4056
展开全部

1、打开eclipse,创建一个Java工程,在此工程里新建一个类;

2、在新建的类中,添加4个运算类;

3、在主方法中调用对应的方法即可完成分数的加减乘除运算了。

具体实现代码如下:

public class Demo {

public static void main(String[] args) {

System.out.println(jia(1, 2));

System.out.println(jian(1, 2));

System.out.println(cheng(1, 2));

System.out.println(chu(1, 2));

}

//加法运算

private static float jia(float x,float y) {

return x + y;

}

//减法运算

private static float jian(float x,float y) {

return x - y;

}

//乘法运算

private static float cheng(float x,float y) {

return x * y;

}

//除法运算

private static float chu(float x,float y) {

return x / y;

}

}

本回答被网友采纳
已赞过 已踩过<
你对这个回答的评价是?
评论 收起
匿名用户
推荐于2018-02-27
展开全部
package Rational;

import java.util.StringTokenizer;
/**
* @author SunKun
* 分数四则运算
*/
public class Calculator {
int numerator; // 分子
int denominator; // 分母

Calculator(){
}

Calculator(int a,int b){
if(a == 0){
numerator = 0;
denominator = 1;
}
else{
setNumeratorAndDenominator(a,b);
}
}

void setNumeratorAndDenominator(int a, int b){ // 设置分子和分母
int c = f(Math.abs(a),Math.abs(b)); // 计算最大公约数
numerator = a / c;
denominator = b / c;
if(numerator<0 && denominator<0){
numerator = - numerator;
denominator = - denominator;
}
}

int getNumerator(){
return numerator;
}

int getDenominator(){
return denominator;
}

int f(int a,int b){ // 求a和b的最大公约数
if(a < b){
int c = a;
a = b;
b = c;
}
int r = a % b;
while(r != 0){
a = b;
b = r;;
r = a % b;
}
return b;
}

Calculator add(Calculator r){ // 加法运算
int a = r.getNumerator();
int b = r.getDenominator();
int newNumerator = numerator * b + denominator * a;
int newDenominator = denominator * b;
Calculator result = new Calculator(newNumerator,newDenominator);
return result;
}

Calculator sub(Calculator r){ // 减法运算
int a = r.getNumerator();
int b = r.getDenominator();
int newNumerator = numerator * b - denominator * a;
int newDenominator = denominator * b;
Calculator result = new Calculator(newNumerator,newDenominator);
return result;
}

Calculator muti(Calculator r){ // 乘法运算
int a = r.getNumerator();
int b = r.getDenominator();
int newNumerator = numerator * a;
int newDenominator = denominator * b;
Calculator result = new Calculator(newNumerator,newDenominator);
return result;
}

Calculator div(Calculator r){ // 除法运算
int a = r.getNumerator();
int b = r.getDenominator();
int newNumerator = numerator * b;
int newDenominator = denominator * a;
Calculator result = new Calculator(newNumerator,newDenominator);
return result;
}

static Calculator qiuyu(double left,double right){ // 求余运算
double point_result = Math.IEEEremainder(left, right);
int r1 = (int)point_result;
double r2 = point_result - r1;
int newNumerator = r1*10000 + (int)(r2*10000);
int newDenominator = 10000;
Calculator result = new Calculator(newNumerator,newDenominator);
return result;
}

static Calculator pow(double left,double right){ // 求幂运算left^right
double point_result = Math.pow(left, right);
int r1 = (int)point_result;
double r2 = point_result - r1;
int newNumerator = r1*10000 + (int)(r2*10000);
int newDenominator = 10000;
Calculator result = new Calculator(newNumerator,newDenominator);
return result;
}

static Calculator max(double left,double right){ // 求两数中的较大值
double point_result = Math.min(left, right);
int r1 = (int)point_result;
double r2 = point_result - r1;
int newNumerator = r1*10000 + (int)(r2*10000);
int newDenominator = 10000;
Calculator result = new Calculator(newNumerator,newDenominator);
return result;
}

static Calculator min(double left,double right){ // 求两数中的较小值
double point_result = Math.min(left, right);
int r1 = (int)point_result;
double r2 = point_result - r1;
int newNumerator = r1*10000 + (int)(r2*10000);
int newDenominator = 10000;
Calculator result = new Calculator(newNumerator,newDenominator);
return result;
}

// 封装了具体运算,主要为对输入进行转换,对输出封装
public static void compute(String data1,String operation,String data2){
StringTokenizer fenxi = new StringTokenizer(data1,"/");
int data1_1 = Integer.parseInt(fenxi.nextToken());
int data1_2 = Integer.parseInt(fenxi.nextToken());
fenxi = new StringTokenizer(data2,"/");
int data2_1 = Integer.parseInt(fenxi.nextToken());
int data2_2 = Integer.parseInt(fenxi.nextToken());

Calculator r1 = new Calculator(data1_1,data1_2);
Calculator r2 = new Calculator(data2_1,data2_2);

Calculator result;
int a,b;
if(operation.equals("+")){ // 两数相加
result = r1.add(r2);
a = result.getNumerator();
b = result.getDenominator();
System.out.println(data1+" "+operation+" " +data2+" = " + a + "/" + b);
}

if(operation.equals("-")){ // 两数相减
result = r1.sub(r2);
a = result.getNumerator();
b = result.getDenominator();
System.out.println(data1+" "+operation+" " +data2+" = " + a + "/" + b);
}

if(operation.equals("*")){ // 两数相乘
result = r1.muti(r2);
a = result.getNumerator();
b = result.getDenominator();
System.out.println(data1+" "+operation+" " +data2+" = " + a + "/" + b);
}

if(operation.equals("/")){ // 两数相除
result = r1.div(r2);
a = result.getNumerator();
b = result.getDenominator();
System.out.println(data1+" "+operation+" " +data2+" = " + a + "/" + b);
}

if(operation.equals("%")){ // 两数求余
double left = (double)data1_1/(double)data1_2;
double right = (double)data2_1/(double)data2_2;
result = qiuyu(left,right);
a = result.getNumerator();
b = result.getDenominator();
System.out.println(data1+" "+operation+" " +data2+" = " + a + "/" + b);
}

if(operation.equals("^")){ // 两数求幂
double left = (double)data1_1/(double)data1_2;
double right = (double)data2_1/(double)data2_2;
result = pow(left,right);
a = result.getNumerator();
b = result.getDenominator();
System.out.println(data1+" "+operation+" " +data2+" = " + a + "/" + b);
}

if(operation.equals("max")){ // 两数中的较大值
double left = (double)data1_1/(double)data1_2;
double right = (double)data2_1/(double)data2_2;
result = max(left,right);
a = result.getNumerator();
b = result.getDenominator();
System.out.println(data1+" "+operation+" " +data2+" = " + a + "/" + b);
}

if(operation.equals("min")){ // 两数中的较小值
double left = (double)data1_1/(double)data1_2;
double right = (double)data2_1/(double)data2_2;
result = min(left,right);
a = result.getNumerator();
b = result.getDenominator();
System.out.println(data1+" "+operation+" " +data2+" = " + a + "/" + b);
}
}
}
本回答被网友采纳
已赞过 已踩过<
你对这个回答的评价是?
评论 收起
收起 1条折叠回答
推荐律师服务: 若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询

为你推荐:

下载百度知道APP,抢鲜体验
使用百度知道APP,立即抢鲜体验。你的手机镜头里或许有别人想知道的答案。
扫描二维码下载
×

类别

我们会通过消息、邮箱等方式尽快将举报结果通知您。

说明

0/200

提交
取消

辅 助

模 式