小学六年级数学题(过程)急!
(题目一)http://hiphotos.baidu.com/%C3%CEt%C6%AE/abpic/item/b949b510c76f798bc2fd7850.jpg(...
( 题目一)
http://hiphotos.baidu.com/%C3%CEt%C6%AE/abpic/item/b949b510c76f798bc2fd7850. jpg (题目二、三)
如果标点符号不清楚,请看这里:
1、 ÷ + + ÷ +
2、分子 ×+×+×-
分母 ++++……+
4 、-+-+--÷
展开
5个回答
展开全部
64又1/17÷9+(13又2/11+11又2/13)÷(5/11+5/13)
=1089/17÷9+(13又2/11+11又2/13)÷(5/11+5/13)
=121+(13又2/11+11又手茄2/13)÷(5/11+5/13)
=121+(145/11+145/13)÷(5/11+5/13)
=121+145(1/11+1/13)÷[5(1/11+1/13)]
=121+145÷5
=121+29
=150
(2006×2007+2007×2008+2006×2008-2)÷(1+2+3+4+5+6+7+……+2006+2007)
=(2006×2007+2007×2008+2006×2008-2)÷[(1+2007)*2007/2]
=(2006×2007+2007×2008+2006×2008-2)÷(1004*2007)
=2006×2007÷(1004*2007)
+2007×2008÷(1004*2007)
+2006×2008÷(1004*2007)
-2÷(1004*2007)
=2006÷1004+2008÷1004+2006×2008÷(1004*2007)-2÷(1004*2007)
=1003/502+2+2006×2÷2007-2÷(1004*2007)
=2-1/502+2+(2007-1)×2÷2007-2÷(1004*2007)
=2-1/502+2+2-2÷2007-2÷(1004*2007)
=6-1/502-2÷2007-1÷(502*2007)
=6-1/502-2/2007-1/(502*2007)
=6-2007/(502*2007)-501/(502*2007)-1/(502*2007)
=6-[2007/(502*2007)+501/(502*2007)+1/(502*2007)]
=6-[(2007+501+1)/(502*2007)]
=6-2510/(502*2007)
=6-4/2007
=5+2003/2007
=5又2003/2007
【(35/6-49/12+63/20-77/30+91/42-105/56)-1又3/8】÷1/8
=[(35/6-49/12+63/20-77/30+91/42-105/56)-1又3/8]×8
=[(5+5/6-(4+1/12)+3+1/20-(2+17/30)+2+7/42-(1+49/56)-(1+3/8)]×8
=[5+5/6-4-1/12+3+1/20-2-17/30+2+7/42-1-49/56-1-3/8]×8
=[5-4+3-2+2-1-1+5/6-1/12+1/20-17/30+7/42-49/56-3/8]×8
=[5/6-1/12+1/20-17/30+7/42-49/56-3/8]×8
=[5/6-1/12+1/20-17/30+1/6-7/8-3/8]×8
=[5/6-1/12+1/20-17/30+5/30-7/8-3/8]×8
=[5/6-1/12+1/20-12/30-7/8-3/8]×8
=[1/2+1/3-(1/3-1/4)+1/隐行4-1/5-2/5-7/8-3/灶薯哗8]×8
=[1/2+1/3-1/3+1/4+1/4-1/5-2/5-7/8-3/8]×8
=[1/2+1/4+1/4-1/5-2/5-7/8-3/8]×8
=[1/2+1/2-3/5-1/8-1]×8
=[1-3/5-1/8-1]×8
=[-3/5-1/8]×8
=-3/5×8-1/8×8
=-24/5-1
=-29/5
=1089/17÷9+(13又2/11+11又2/13)÷(5/11+5/13)
=121+(13又2/11+11又手茄2/13)÷(5/11+5/13)
=121+(145/11+145/13)÷(5/11+5/13)
=121+145(1/11+1/13)÷[5(1/11+1/13)]
=121+145÷5
=121+29
=150
(2006×2007+2007×2008+2006×2008-2)÷(1+2+3+4+5+6+7+……+2006+2007)
=(2006×2007+2007×2008+2006×2008-2)÷[(1+2007)*2007/2]
=(2006×2007+2007×2008+2006×2008-2)÷(1004*2007)
=2006×2007÷(1004*2007)
+2007×2008÷(1004*2007)
+2006×2008÷(1004*2007)
-2÷(1004*2007)
=2006÷1004+2008÷1004+2006×2008÷(1004*2007)-2÷(1004*2007)
=1003/502+2+2006×2÷2007-2÷(1004*2007)
=2-1/502+2+(2007-1)×2÷2007-2÷(1004*2007)
=2-1/502+2+2-2÷2007-2÷(1004*2007)
=6-1/502-2÷2007-1÷(502*2007)
=6-1/502-2/2007-1/(502*2007)
=6-2007/(502*2007)-501/(502*2007)-1/(502*2007)
=6-[2007/(502*2007)+501/(502*2007)+1/(502*2007)]
=6-[(2007+501+1)/(502*2007)]
=6-2510/(502*2007)
=6-4/2007
=5+2003/2007
=5又2003/2007
【(35/6-49/12+63/20-77/30+91/42-105/56)-1又3/8】÷1/8
=[(35/6-49/12+63/20-77/30+91/42-105/56)-1又3/8]×8
=[(5+5/6-(4+1/12)+3+1/20-(2+17/30)+2+7/42-(1+49/56)-(1+3/8)]×8
=[5+5/6-4-1/12+3+1/20-2-17/30+2+7/42-1-49/56-1-3/8]×8
=[5-4+3-2+2-1-1+5/6-1/12+1/20-17/30+7/42-49/56-3/8]×8
=[5/6-1/12+1/20-17/30+7/42-49/56-3/8]×8
=[5/6-1/12+1/20-17/30+1/6-7/8-3/8]×8
=[5/6-1/12+1/20-17/30+5/30-7/8-3/8]×8
=[5/6-1/12+1/20-12/30-7/8-3/8]×8
=[1/2+1/3-(1/3-1/4)+1/隐行4-1/5-2/5-7/8-3/灶薯哗8]×8
=[1/2+1/3-1/3+1/4+1/4-1/5-2/5-7/8-3/8]×8
=[1/2+1/4+1/4-1/5-2/5-7/8-3/8]×8
=[1/2+1/2-3/5-1/8-1]×8
=[1-3/5-1/8-1]×8
=[-3/5-1/8]×8
=-3/5×8-1/8×8
=-24/5-1
=-29/5
展开全部
题目一:解
(63+18/17)雹核并×1/9+(氏核145/11+145/13)÷(5/源迹11+5/13)
=7+2/17+145÷5
=36+2/17
(63+18/17)雹核并×1/9+(氏核145/11+145/13)÷(5/源迹11+5/13)
=7+2/17+145÷5
=36+2/17
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
展开全部
1 =(64*17+1)/17*9+{(13*11*13+2*13+11*13*11+2*11)/(11*13)}÷{(5*13+5*11)/(11*13)}
=121/17+(13*11*13+2*13+11*13*11+2*11)/(5*13+5*11)
=121/17+{13*11*(13+11)+2*(13+11)}/{5*(13+11)}
=121/17+(13*11+2)/5
=121/17+29
=36(2/17)
2 =2{2007*2008-2*2007+2007*2008+2007*2008-2008-2}/{(1+2007)*2007}
=2{2007*2008-2*2007+2007*2008+2007*2008-2008-2)/(2007*2008)
=2-4/2008+2+2-2/2007-4/(2007*2008)岁源
=6-(2007*4+2*2008+4)/(2007*2008)
=6-2/669
=5(667/669)
3 =(70/12-49/12+189/60-154/60+91/42-105/56-11/8)*8
=(21/仔中12+35/60+91/42-105/56-11/8)*8
=14+14/3+364/念雀山21-105/7-11
=3+(98+364-315)/21
=3+7
=10
=121/17+(13*11*13+2*13+11*13*11+2*11)/(5*13+5*11)
=121/17+{13*11*(13+11)+2*(13+11)}/{5*(13+11)}
=121/17+(13*11+2)/5
=121/17+29
=36(2/17)
2 =2{2007*2008-2*2007+2007*2008+2007*2008-2008-2}/{(1+2007)*2007}
=2{2007*2008-2*2007+2007*2008+2007*2008-2008-2)/(2007*2008)
=2-4/2008+2+2-2/2007-4/(2007*2008)岁源
=6-(2007*4+2*2008+4)/(2007*2008)
=6-2/669
=5(667/669)
3 =(70/12-49/12+189/60-154/60+91/42-105/56-11/8)*8
=(21/仔中12+35/60+91/42-105/56-11/8)*8
=14+14/3+364/念雀山21-105/7-11
=3+(98+364-315)/21
=3+7
=10
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
展开全部
与山顶洞人的区别
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询