先化简再求值:(x-1分之x的平方-x+1)除以1-x分之4x的平方-4x+1,其中x满足x的平方+x-2=0
展开全部
x²+x-2=0
(x-1)(x+2)=0x=1或x=-2(x²-x+1)/(x-1)÷(4x²-4x+1)/(1-x)=(x²-x+1)/(x-1)*(1-x)/(4x²-4x+1)=-(x²-x+1)/(4x²-4x+1)=-(x²-x+1)/(2x-1)²当x=1时(x²-x+1)/(x-1)÷(4x²-4x+1)/(1-x)=-(x²-x+1)/(2x-1)²=-1/1=-1当x=-2时(x²-x+1)/(x-1)÷(4x²-4x+1)/(1-x)=-(x²-x+1)/(2x-1)²=-7/25
(x-1)(x+2)=0x=1或x=-2(x²-x+1)/(x-1)÷(4x²-4x+1)/(1-x)=(x²-x+1)/(x-1)*(1-x)/(4x²-4x+1)=-(x²-x+1)/(4x²-4x+1)=-(x²-x+1)/(2x-1)²当x=1时(x²-x+1)/(x-1)÷(4x²-4x+1)/(1-x)=-(x²-x+1)/(2x-1)²=-1/1=-1当x=-2时(x²-x+1)/(x-1)÷(4x²-4x+1)/(1-x)=-(x²-x+1)/(2x-1)²=-7/25
本回答由提问者推荐
已赞过
已踩过<
评论
收起
你对这个回答的评价是？
推荐律师服务：
若未解决您的问题，请您详细描述您的问题，通过百度律临进行免费专业咨询
