数学 第4题
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z= -1 +i
|z| = √2
arg z = arctan( 1/-1) = 3π/4
z= √2[ cos(3π/4) + isin(3π/4) ]
w
= z^(1/3)
= 2^(1/6) .[ cos(π/4) + isin(π/4) ]
= 2^(1/6) .[ √2/2 + i(√2/2) ]
= 2^(-1/3) . ( 1 + i)
|z| = √2
arg z = arctan( 1/-1) = 3π/4
z= √2[ cos(3π/4) + isin(3π/4) ]
w
= z^(1/3)
= 2^(1/6) .[ cos(π/4) + isin(π/4) ]
= 2^(1/6) .[ √2/2 + i(√2/2) ]
= 2^(-1/3) . ( 1 + i)
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