这道题怎么分解因式的？求详解
2个回答
展开全部
原式=2（3x^4-2x^2-1）-7x^2(x-1)
=2(3x^2+1)(x^2-1)-7x^2(x-1)
=(6x^2+2)(x-1)(x+1)-7x^2(x-1)
=(x-1)[(6x^2+2)(x+1)-7x^2]
=(x-1)[6x^3+6x^2+2x+2-7x^2]
=(x-1)(6x^3-x^2+2x+2)
=(x-1)(2x+1)(3x^2-2x+2)
=2(3x^2+1)(x^2-1)-7x^2(x-1)
=(6x^2+2)(x-1)(x+1)-7x^2(x-1)
=(x-1)[(6x^2+2)(x+1)-7x^2]
=(x-1)[6x^3+6x^2+2x+2-7x^2]
=(x-1)(6x^3-x^2+2x+2)
=(x-1)(2x+1)(3x^2-2x+2)
本回答由提问者推荐
已赞过
已踩过<
评论
收起
你对这个回答的评价是？
推荐律师服务：
若未解决您的问题，请您详细描述您的问题，通过百度律临进行免费专业咨询
