12分之7x[4分之1 ÷(3分之1-0.25)]的过程?
1个回答
2020-04-01
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分数写作“分子/分母”,
(7/12)×[(1/4)÷(1/3-0.25)]
=(7/12)×[(1/4)÷(1/3-1/4)]
=(7/12)×[(1/4)÷(1/12)]
=(7/12)÷(1/12)×(1/4)
=7×(1/4)
=7/4
(7/12)×[(1/4)÷(1/3-0.25)]
=(7/12)×[(1/4)÷(1/3-1/4)]
=(7/12)×[(1/4)÷(1/12)]
=(7/12)÷(1/12)×(1/4)
=7×(1/4)
=7/4
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