Question

绝对值不等式,若a>0

数学绝对值不等式的问题 若0 0,a不等于1,比较|log (1-x)|与|log (1+x)|的大小,并说明理由 请帮我解决这道题目,请写出详细的过程,写的好的给高分,谢谢~!很急,希望大家都来帮忙~!谢谢

Answer 1

1° 当0<a<1时,|log(a)(1-x)|=log(a)(1-x),|log(a)(1+x)|=-log(a)(1+x) bdsfid="120" |log(a)(1-x)|-|log(a)(1+x)|
=log(a)(1-x)+log(a)(1+x)
=log(a)(1-x^2)>0
2° 当a>1时, |log(a)(1-x)|=-log(a)(1-x),|log(a)(1+x)|=log(a)(1+x)
|log(a)(1-x)|-|log(a)(1+x)|
=-[ log(a)(1-x)+log(a)(1+x) ]
=-log(a)(1-x^2)>0
综上所述：|log(a)(1-x)|>|log(a)(1+x)|
希望采纳···</a