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没有问题,绝对正确,请放心.
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k∈R , k≠0
dkx = kdx <===> k*dx = dkx
d(x/k) = (1/k)dx <===> (1/k)dx = d(x/k)
⑥=∫[2/cos^2(x/2)]dx /3[(tan(x/2)/√3)^2 +1]
= 2∫[sec^2(x/2)dx] /3[(tan(x/2)/√3)^2 +1]
= 4∫[sec^2(x/2)d(x/2)] /3[(tan(x/2)/√3)^2 +1]
= 4∫[dtan(x/2)] /3[(tan(x/2)/√3)^2 +1]
= 4/√3∫[dtan(x/2)/√3] /[(tan(x/2)/√3)^2 +1]
=⑦
dkx = kdx <===> k*dx = dkx
d(x/k) = (1/k)dx <===> (1/k)dx = d(x/k)
⑥=∫[2/cos^2(x/2)]dx /3[(tan(x/2)/√3)^2 +1]
= 2∫[sec^2(x/2)dx] /3[(tan(x/2)/√3)^2 +1]
= 4∫[sec^2(x/2)d(x/2)] /3[(tan(x/2)/√3)^2 +1]
= 4∫[dtan(x/2)] /3[(tan(x/2)/√3)^2 +1]
= 4/√3∫[dtan(x/2)/√3] /[(tan(x/2)/√3)^2 +1]
=⑦
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