Question

化简逻辑函数式f=ab非+c+a非c非d+bc非d？

大神求解

Answer 1

因为 “非”运算符在网页上敲不出来，就用单撇号来表示：

F = AB' + C(1+A'D) + A'C'D + BC'D 注：1+A'D = 1
= AB' + C + (C+C')A'D + BCD 注：C+C' = 1
= AB' + C+ A'D + BC'D
= AB' + C(1+BD) + C'BD + A'D
= AB' + C + (C+C')BD + A'D
= AB' + C+ BD + A'D
= AB' + C + D(B+A')
= AB' + (AB')'D + C 注：A'+B = A' + (B')' = (A'B)'
= AB'(1+D) + (AB')'D + C
= AB' + [AB' + (AB')']D + C
= AB' + D + C
上面就是化简后的结果。希望能够帮到你！