Question

一到初二数学题，急啊，要有过程啊

判断关于x的方程（k+1）^2+（3k+2）x+k-二分之一=0根的情况

Answer 1

△=(3k+2)²-4(k+1)(k-1/2)
=9k²+12k+4-4(k²+k/2-1/2)
=5k²+10k+6
=5(k+1)²+1>0
所以方程有两个不同解

Answer 2

△=(3k+2)²-4(k+1)(k-1/2)
=9k²+12k+4-4(k²+k/2-1/2)
=5k²+10k+6
=5(k+1)²+1>0
故方程有两个不同解