【（√6+√ 3）（√3+√2）】除以（√6+4√3+3√2）的值 详解，写得好我给10
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[(√6+√3)+(3√3+3√2)]/[(√6+√3)(3√3+3√2)]
=(√6+√3)/[(√6+√3)(3√3+3√2)]+(3√3+3√2)/[(√6+√3)(3√3+3√2)]
=1/(3√3+3√2)+1/(√6+√3)
=(1/3)/(√3+√2)+1/(√6+√3)
=(√3-√2)/3+(√6-√3)/3
=(√6-√2)/3
所以[(√6+√3)(3√3+3√2)]/[(√6+√3)+(3√3+3√2)]=3/(√6-√2)
3[(√6+√3)(√3+√2)]/(√6+4√3+3√2)=3/(√6-√2)=3(√6+√2)/4
(√6+√3)(√3+√2)/(√6+4√3+3√2)=3/(√6-√2)=(√6+√2)/4
=(√6+√3)/[(√6+√3)(3√3+3√2)]+(3√3+3√2)/[(√6+√3)(3√3+3√2)]
=1/(3√3+3√2)+1/(√6+√3)
=(1/3)/(√3+√2)+1/(√6+√3)
=(√3-√2)/3+(√6-√3)/3
=(√6-√2)/3
所以[(√6+√3)(3√3+3√2)]/[(√6+√3)+(3√3+3√2)]=3/(√6-√2)
3[(√6+√3)(√3+√2)]/(√6+4√3+3√2)=3/(√6-√2)=3(√6+√2)/4
(√6+√3)(√3+√2)/(√6+4√3+3√2)=3/(√6-√2)=(√6+√2)/4
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