设m-n=1/4,m+n=2,求[m²n²/(m²+2mn+n²)-2/mn÷(1/m+1/n)²]●1/(m-n)的值 5
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[(m²+n²)/(m²+2mn+n²)-2/mn÷(1/m+1/n)²]×1/(m-n)
=[(m²+n²)/(m+n)²-2/mn÷(m+n)²/m²n²]×1/(m-n)
=[(m²+n²)/(m+n)²-2/mn×m²n²/(m+n)²]×1/(m-n)
=[(m²+n²)/(m+n)²-2mn/(m+n)²]×1/(m-n)
=[m²+n²-2mn)/(m+n)²]×1/(m-n)
=[(m-n)²/(m+n)²]×1/(m-n)
=(m-n)/(m+n)²
=(1/4)/2²
=1/16
=[(m²+n²)/(m+n)²-2/mn÷(m+n)²/m²n²]×1/(m-n)
=[(m²+n²)/(m+n)²-2/mn×m²n²/(m+n)²]×1/(m-n)
=[(m²+n²)/(m+n)²-2mn/(m+n)²]×1/(m-n)
=[m²+n²-2mn)/(m+n)²]×1/(m-n)
=[(m-n)²/(m+n)²]×1/(m-n)
=(m-n)/(m+n)²
=(1/4)/2²
=1/16
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