已知x=√2+1,求(x+1/x^2-x-x/x^2-2x+1)÷1/x
展开全部
(x+1/x^2-x-x/x^2-2x+1)÷1/x
=[(x+1)/x(x-1)-x/(x-1)²]*x
=[(x+1)(x-1)-x²]/x(x-1)²*x
=(x²-1-x²)/x(x-1)²*x
=-1/x(x-1)²*x
=-1/(x-1)²
=-1/(√2+1-1)²
=-1/2
=[(x+1)/x(x-1)-x/(x-1)²]*x
=[(x+1)(x-1)-x²]/x(x-1)²*x
=(x²-1-x²)/x(x-1)²*x
=-1/x(x-1)²*x
=-1/(x-1)²
=-1/(√2+1-1)²
=-1/2
本回答由提问者推荐
已赞过
已踩过<
评论
收起
你对这个回答的评价是？
推荐律师服务：
若未解决您的问题，请您详细描述您的问题，通过百度律临进行免费专业咨询
