Question

a²b³—（ ）=-3a²b³ 4/1xy—（5x²y²）—（+1/6xy）—2x²y²+7+（

a²b³—（ ）=-3a²b³ 4/1xy—（5x²y²）—（+1/6xy）—2x²y²+7+（-3x²y²)要带过程

还有a²/2—a²/3+a²/6

Answer 1

1.4a²
2.
3.a²/2-a²/3+a²/6
=a²/6（3-2+1）
=a²/6 ×2
=1/3 a²

Answer 2

4a²b³ ()= a²b³+ 3a²b³= 4a²b³

4/1xy—（5x²y²）—（+1/6xy）—2x²y²+7+（-3x²y²)
=（4-1/6）xy+（-5-2-3）x²y²+7
=23/6xy-10x²y²+7

a²/2—a²/3+a²/6
=（1/2+1/3+1/6）a²
=a²