Question

求个c语言通讯录代码，要求如下

Answer 1

#include<iostream>
#include<string>
#include<cstring>
using namespace std;
int show();
int add();
int lookup();
int print();
int isFull(int a);
int totalnumber;
int counter=0;
struct ren
{
	int xuhao;
	char xingming[20];
	char haoma[12];
} user[100];
int main()
{	cout<<"please enter the total number to save:";
	cin>>totalnumber;
	show();
	return 0;
}
int show()
{
	cout<<"what do you want to do?"<<endl;
	cout<<"1.Add a new contact."<<endl;
	cout<<"2.Look up a existing number."<<endl;
	cout<<"3.Print all contacts."<<endl;
	cout<<"4.Exit."<<endl;
	int i;
	cin>>i;
	if(i==1)
		add();
	else if(i==2)
		lookup();
	else if(i==3)
		print();
	else if(i==4)
		return 0;
}
int add()
{
	cout<<"enter a name:";
	char name[20];
	cin>>name;
	cout<<"enter the phone number:";
	char number[12];
	cin>>number;
	user[counter].xuhao=counter;
	strcpy(user[counter].xingming,name);
	strcpy(user[counter].haoma,number);
	cout<<"the new contact is saved!"<<endl;
	++counter;
	isFull(counter);
	show();
	return 0;
}
int lookup()
{
	int j=0;
	cout<<"please enter the name to look up:";
	char name[20];
	cin>>name;
	for(int i=0;i<counter;++i)
	{
		if(strcmp(user[i].xingming,name)==0)
		{
			cout<<user[i].xuhao+1<<" "<<user[i].xingming<<" "<<user[i].haoma<<endl;
			j=1;
			break;
		}
	}
	if(j==1)
		show();
	else
	{
		cout<<"not find."<<endl;
		show();
	}
	return 0;
}
int print()
{
	cout<<"the total contacts are:"<<endl;
	for(int i=0;i<counter;++i)
		cout<<user[i].xuhao+1<<"  "<<user[i].xingming<<"  "<<user[i].haoma<<endl;
	cout<<"enter OK to go back."<<endl;
	string answer;
	cin>>answer;
	if(answer=="OK"||answer=="ok")
		show();
	else
		return 0;
}
int isFull(int a)
{
	if(a==totalnumber)
	{
		cout<<"the number of contacts reachs the totalnumber."<<endl;
		cout<<"do you want to print the total contacts?(Y/N)"<<endl;
		string j;
		cin>>j;
		if(j=="Y"||j=="y")
			print();
		else
			show();
	}
	return 0;
}
注：1.名字不要超过19个字符，2.第一个选择输入前边的序号（1或2或3或4）就可以，

Answer 2

用单链表做

Answer 3

等有空帮你写