Question

高手请指点，用matlab画图怎么只出现坐标面而不出现图像？谢谢！程序如下

Ex1=60;
Ex2=1.7;
En1=6;
En2=0.5;
He1=0.1;
He2=0.01;
n=5000;
for i=1:n
Enn1=randn(1)* He1 +En1;
x(i)= randn(1)* Enn1+Ex1;
Enn2=randn(1)* He2 +En2;
y(i)= randn(1)* Enn2 +Ex2;
z(i)=exp(-(x(i)-Ex1)^2/(2*Enn1^2)- (y(i)-Ex2)^2/(2*Enn2^2));
plot3(x(i),y(i),z(i))
grid on;
end

Answer 1

%平面六杆机构运动分析%(1)----导杆位置%各杆长度输入l1=input('机架长度(mm)');l2=input('曲柄长键早度(mm)');l3=input('导杆长度(mm)');l4=input('连杆长(mm)');l5=input('滑块5到坐标原点距离(mm)');omg=input('曲柄角速度(rad/s)');dr=pi/180.0;%角度与弧度的转换%机构的初始位置th(1)=0.0;dth=5*dr;%循环增量%计算导杆启亮棚的位置角度th和滑块的s23%曲柄0-360度转,步长为5度fori=1:72ct=i*dth;ifth(1)<=90*drth3=atan(2*(l1+l2*sin(th(1)))/(l2*cos(th(1))));elseifth(1)<=270*drth3=atan(2*(l1+l2*sin(th(1)))/(l2*cos(th(1))))+pi;elseth3=atan(2*(l1+l2*sin(th(1)))/(l2*cos(th(1))));ends3=(l1+l2*sin(th(1))+l2*cos(th(1)))/(sin(th3)+cos(th3));w(i,:)=[th(1)/drth3/drs3];%矩阵th(1)=th(1)+dthendend%(2)-计算导杆3的角速度和滑块2速度fori=1:72c(2)=(i-1)*dth;C=[-w(i,3)*sin(w(i,2)*dr)*cos(w(i,2)*dr);w(i,3)*cos(w(i,2)*dr)*sin(w(i,2)*dr)];D(1)=[-l2*omg^2*cos(c(2))+2*v23(i,2)*v23(i,3)*sin(w(i,2)*dr)+w(i,3)*omg^2*cos(w(i,2)*dr)];D(2)=[-l2*omg^2*sin(c(2))-2*v23(i,3)*v23(i,2)*cos(w(i,2)*dr)+w(i,3)*8*omg^2*sin(w(i,2)*dr)];a=inv(C)*D';a1=a(1);a2=a(2);a23(i,:)=[c(2)/dra1a2];%矩阵[曲柄转角导杆角加速度滑块加速度]end%(4)----------------计算滑块5的位移fori=1:72..end%绘制滑块5的位移subplot(2,2,1)plot(s45(:,1),s45(:,3))gridxlabel('曲柄转角')ylabel('滑块位移')%----------计算滑块5速度fori=1:72et=(i-1)*dth;E=[-l4*sin(s45(i,2)*dr)-1;l4*cos(s45(i,2)*dr)];F=[l4*v23(i,2)*sin(w(i,2)*dr);-l4*v23(i,2)*cos(w(i,2)*dr)];b=inv(E)*F;b1=b(1);b2=b(2);b23(i,:)=[et/drb1b2];end%绘制滑块5的速度曲线subplot(2,2,3)plot(d45(:,1),d45(:,2))gridxlabel('曲柄转角悄则')ylabel('连杆角加速度')subplot(2,2,4)plot(d45(:,1),d45(:,3))gridxlabel('曲柄转角')ylabel('滑块加度度')