Question

有关C语言函数的问题求大神解答~

题目：写一个函数，将一个字符串中的元音字母复制到另一字符串，然后输出。
我写的代码：
#include <stdio.h>
int main()
{
int judge(char m[100],char n[100]);
int a[100],b[100];
printf("请输入一个字符串：");
gets(a);
gets(judge(a[100],b[100]));
puts(b);
return 0;
}
int judge(char m[100],char n[100])
{
int i,j;
while(m[i]!='\0')
for(i=0,j=0;i<100;i++)
{
if(m[i]=='a'||m[i]=='e'||m[i]==i||m[i]=='o'||m[i]=='u'||m[i]=='A'||m[i]=='E'||m[i]=='I'||m[i]=='O'||m[i]=='U')
n[j]=m[i];
j++;
}
return n[100];
}

报错：
warning C4133: 'function' : incompatible types - from 'int [100]' to 'char *'

warning C4047: 'function' : 'char *' differs in levels of indirection from 'int '
warning C4024: 'judge' : different types for formal and actual parameter 1
warning C4047: 'function' : 'char *' differs in levels of indirection from 'int '
warning C4024: 'judge' : different types for formal and actual parameter 2
warning C4047: 'function' : 'char *' differs in levels of indirection from 'int '
warning C4024: 'gets' : different types for formal and actual parameter 1
warning C4133: 'function' : incompatible types - from 'int [100]' to 'const char *'
warning C4700: local variable 'b' used without having been initialized

我是初学者，很多都不懂，请大神们解答一下说详细一点~谢谢啦~

Answer 1

#include <stdio.h>
int main()
{
void judge(char m[100],char n[100]);
char a[100],b[100];
printf("请输入一个字符串：");
gets(a);
judge(a,b);
puts(b);
return 0;
}
void judge(char m[],char n[])
{
int i=0,j = 0;
while(m[i]!='\0')
{
if(m[i]=='a'||m[i]=='e'||m[i]=='i'||m[i]=='o'||m[i]=='u'||m[i]=='A'||m[i]=='E'||m[i]=='I'||m[i]=='O'||m[i]=='U')
{
n[j]=m[i];
j++;
}
i ++;
}
n[j] = '\0';

//return n;
}
这样就对了

追问

void不是应该是无参函数用的吗？它这个有参数为什么用void是正确的啊？

追答

无参不用返回的，数组传过就能改数组里面的值了，不用返回值的，你看到指针你就懂了，这里其实就是指针，数组名就是指针