Question

两个m×n的矩阵，用C++编写程序实现矩阵的加法运算（两个矩阵中的元素一一对应）

Answer 1

int a[m][n],b[m][n];
分别2个数组赋值
int i,j;
for(i = 0; i < m; i++)
for(j = 0; j < n; j++)
a[i][j] += b[i][j];
最后输出a数组元素就是结果了

Answer 2

#include <iostream>

using namespace std;

int main()
{
int i, j, m, n;
cin >> m >> n;
int **ia = new int *[m];

for (i = 0; i < m; ++i)
{
ia[i] = new int[n];

for (j = 0; j < n; ++j)
cin >> ia[i][j];
}

cout << endl;

for (i = 0; i < m; ++i)
{
for (j = 0; j < n; ++j)
cout << ia[i][j] << ' ';

cout << endl;
}

cout << endl;

return 0;
}